I was wondering why the reaction between carbon dioxide and calcium hydroxide is considered an acid-base reaction when there are no hydrogens which are donated or received (at least that"s what I can see). It looks like a double displacement reaction to lớn me.
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I will be very thankful if anyone can clear up my confusion.
My guess is that your confusion stems from the fact that there are 3 main definitions of acid/base.
In introductory orsini-gotha.com, we cover the concept of Arrhenius acid/base, where the acid is a proton donor and the base is a hydroxide donor.
$$ceHCl + NaOH -> H2O + NaCl$$
As we learn more, we"re introduced to lớn the concept of Brønsted-Lowry acid/base, where the acid is a proton donor và the base is a proton acceptor.
$$ceHCl + NH3 -> NH4+ + Cl-$$
Finally, we"re introduced to the concept of Lewis acid/base, where the acid is an electron-pair acceptor và the base is an electron-pair donor.
Xem thêm: Tích Số Ion Của Nước Là Gì Và Bằng Bao Nhiêu Ở 25, Tích Số Ion Của Nước Là Gì
Your example is confusing probably because it is one of these cases. Hydroxide has a lone pair (Lewis base). That lone pair interacts with an empty $pi*$ orbital in carbon dioxide (a Lewis acid) lớn create a new bond (bicarbonate). The bicarbonate then reacts with water in a more familiar way, so technically, there are multiple acid/base interactions happening even in your simple example.
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edited Oct 22, 2019 at 12:01
answered Oct 21, 2019 at 20:18
ZheZhe
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What about this ?
$$ceCO2(aq) + H2O H2CO3$$
$$ceH2CO3 H+ + HCO3-$$
$$ceHCO3- H+ + CO3^2-$$
$$ceCa(OH)2 Ca(OH)+ + OH-$$
$$ceCa(OH)+ Ca^2+ + OH-$$
$$ceH+ + OH- H2O$$
$$ceCa^2+ + CO3^2- CaCO3 v$$
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answered Oct 21, 2019 at 18:57
PoutnikPoutnik
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An acid-base reaction is a reaction where a base is destroyed by an acid.Here the base OH- is present in the molecule Ca(OH)2. And it is destroyed by CO2, which in solution is acid as it produced the acid H2CO3 with water.So the reaction CO2 + Ca(OH)2 is an acid-base reaction
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answered Oct 21, 2019 at 19:36
MauriceMaurice
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